WebMar 1, 2024 · Answer: Volume = 19.68 ml Explanation: The equation of the reaction is given as; HNO3 + KOH ---> KNO3 + H2O 1 mol of HNO3 reacts 1 mol of KOH Converting 0.276 g of KOH to mol; Number of moles = Mass / Molar mass Number of moles = 0.276g / 56.1056 g/mol Number of moles = 0.00492 Since the mole relationship is 1 = 1; WebHow many millilitres of 0.250 M NaOH are required to neutralize 0.200 g of oxalic acid dihydrate (H2C2O4· 2H2O). This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer
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WebVideo Filternox® FMS models are specially designed for low flow installations. FMS models can be used for prefiltration as well as final filtration for various water sources containing … WebNov 21, 2024 · The mass of the bob is 0.250 kg. The length of the string is 22.0 cm. The angle made by the string to the vertical is 24 degrees. The centripetal force in the vertical direction can be given as, The centripetal force in the horizontal direction can be given as, As the force in horizontal direction is equal to the force in vertical direction. Thus, bisexuality among primates
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WebJul 10, 2016 · 2.5 mL First lets get the units the same for the suspension (in mg) and the required amount of ampicillin (in g): 1 g = 1000 mg -> 0.125 g = 125 mg For easy calculation and for better understanding of what you are doing, it is best to then calculate how many mg is in 1 mL: (250 mg) / (5.0 mL)= (50 mg)/(1 mL) So 1 mL of the solution … WebJun 26, 2024 · Explanation: Step 1: Data given Mass of an unknown molecular compound = 27.6 grams Mass of benzene = 0.250 kg Kf of benzene = 5.12 °C/m freezing point depression of 3.69 °C Step 2: Calculate molality ΔT = i*Kf*m ⇒with ΔT = reezing point depression of 3.69 °C ⇒with i = the van't Hoff factor of Benzene = 1 ⇒with Kf = 5.12 °C/m WebFeb 6, 2016 · How much 0.05 M HCl solution can be made by diluting 250 mL of 10 M HCl? Chemistry Solutions Dilution Calculations 1 Answer anor277 Feb 6, 2016 Calculate the number of MOLES of H Cl in the starting material. The second volume of solution depends on this molar quantity. Explanation: So, there 250 × 10−3L ×10 ⋅ mol ⋅ L −1 = 250 × 10−2 … dark chrome plating