WebThe maximum diagonal index is simply ( (N-1) + (M-1)) = N + M - 2 So to solve the problem we simply need to iterate through all possible diagonal indices (denote this as s) and find all possible pairs (i, j) such that i + j = s. The only thing we need to … WebFeb 18, 2024 · why don't you try to keep your algorithm as easy as possible? one thing to keep things simple is to use an int[][] as source; you can directly calculate the length of each diagonal ; you can directly calculate the indice (x/y) of each element of the diagonal; you can calculate the diagonal from the top and from the right in one step; if you init your …
Diagonal difference using Linq - Code Review Stack Exchange
WebDec 22, 2016 · Update. I was curious about the performance, and went an extra mile here. I created a "microbenchmark". As usual, such microbenchmarks should be taken with a grain of salt.But I took into account several basics for this: The different implementations are run alternatingly, in several passes, with different inputs, several times, to give the JIT a … Webdef get_numerology_compatibility (bday_num1: int, bday_num2: int, num_compatibility_table: list) -> int: """ Return the compatibility percentage (one of `HIGH_COMPATIBILITY`, `LOW_COMPATIBILITY`, and `MID_COMPATIBILITY`) for `bday_num1` and `bday_num2`, which are the numerology numbers of two birthdays, disney nursery lamp
Diagonal Traverse ii - Coding Ninjas
WebMar 14, 2013 · Zigzag (or diagonal) traversal of Matrix; Print matrix in diagonal pattern; Program to print the Diagonals of a Matrix; Efficiently … WebIt should be clear that the sum of row i and column j is equal to the index of the diagonal (diagonal number ... class Solution(object): def findDiagonalOrder(self, matrix): """ :type … disney nutcracker logo